Hi All,
Lets consider a t1 link on a routers serial interface. The link is having 4 PVC. 2 are on s1/0.1 and one on s1/0.2 and one more on the s1/0.3. If i issue no command of bandwidth control, then how the EIGRP is going to use this BW for each PVC on serial S1/0.1 and on S1/0.2 or S1/0.3.
I could understand under defaults, each interface would have around (1544/3=) 515 Kbps. But how about the 2 PVC existing on the Serial S1/0.1.
Documentation ref will also be helpful.
Cheers!
Ravi
Bandwidth values for physical interfaces are set at statrup time (based
on the hardware)
for subinterfaces (logical) youset it yourself.
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Hi,
As said earlier I have not specified any BW command. Please let us know how the BW is distributed on default conditions. A ref document will also be helpful.
Cheers!
Ravi
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There are default bandwidth definitions for all interfaces, its nothing you set. For serial, the default is t-1 speeds
bandwidth
To set a bandwidth value for an interface, use the bandwidth interface configuration command. Use theno form of this command to restore the default values.
bandwidth kilobitsno bandwidth
Syntax Description
# kilobits | # Intended bandwidth in kilobits per second. For a full bandwidth DS3, enter the value 44736. |
Default
Default bandwidth values are set during startup and can be displayed with the EXEC command show interfaces.
Its an old reference.
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Lets consider a t1 link on a routers serial interface. The link is having 4 PVC. 2 are on s1/0.1 and one on s1/0.2 and one more on the s1/0.3. If i issue no command of bandwidth control, then how the EIGRP is going to use this BW for each PVC on serial S1/0.1 and on S1/0.2 or S1/0.3.
I could understand under defaults, each interface would have around (1544/3=) 515 Kbps. But how about the 2 PVC existing on the Serial S1/0.1.
I think I got the answer:
Since, we have not specified any BW command the default is 1544so for subinterfaces with one PVC, each would you use around (1544*50%=)772Kbps for EIGRP traffic.
And for the subinterface with 2 PVC it would be round (1544*(1/2)*50%=)386 Kbps.
Hope now this is absolutely right!
Below are ref links:
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